program to print/display all ascii values of letters from A to Z and a to z..

//program  to print/display all ascii values of letters from A to Z and a to z..

#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
char k='A';
while(k<='Z')
{
printf("chracter=%c and ascii value=%d | \t character=%c and ascii value=%d\n",k,k,k+32,k+32);
k++;
}
getch();
}

note:
logic applied:
we have printed character and its asciii value.
ASCII value of 'A' is 65 and 'a' is 97.
We can see difference of both is 32 so we can get ascii value by adding 32 to respective values and charcaters.

program to print/display all characters from a to z.

//program  to print/display all characters from a to z.
#include<stdio.h>
#include<conio.h>
void main()
{
int k=97;

while(k<=122)
   {
           printf("%c,",k);
      
    k++;
   }
getch();
}

logic applied:
1)You should know ascii value of all characters then apply that in loop.
ascii value of 'a' is 97 and z is 122.
so apply this value in a loop and print as a character(%c).
or
2)You can use all characters stored in a string and then display one by one.
e.g.
int j;
char string[]="abcdefghijklmnopqrstuvwxyz";
for(j=0;string[j]!='\0';j++)
{
  printf("%c\n",string[j]);
}

put this code in side void main and execute them . you get output.

program to get/sum of all even numbers lying between 1 to n natural numbers

//program  to get/sum of all even numbers lying between 1 to n natural numbers
#include<stdio.h>
#include<conio.h>
void main()
{
int k=0,n,sum=0;                         //you can take k=1, even
printf("enter value of 'n'\n");
scanf("%d",&n);
while(k<=n)
   {
      if(k%2==0)
      {      sum=sum+k;
      }
    k++;
   }
printf("the sum=%d",sum);getch();
getch();
}

-----------------------------
we can also write this program as shown below.
-------------------------------------
//program  to get/sum of all even numbers lying between 1 to n natural numbers
#include<stdio.h>
#include<conio.h>
void main()
{
int k=0,n,sum=0;                         
printf("enter value of 'n'\n");
scanf("%d",&n);
while(k<=n)
   {
            sum=sum+k;
      
    k=k+2;
   }
printf("the sum=%d",sum);
getch();
getch();
}