program to print/display all perfect square numbers lying between 1 and 'n'.

//program to print/display all perfect square numbers lying between 1 and 'n'.
#include<stdio.h>

#include<conio.h>

#include<math.h>void main()
{
   int factors,i,n;
   printf("enter  positive number for 'n'\n");
  scanf("%d",&n);
  for(i=1;i<=n;i++)
    {
      if(sqrt(i)==int(sqrt(i))
        {                

          printf("the perfect squares are=%d ",i);
        }

  }

getch();
}
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logics in mind:
->enter a number for range to get perfect square
->we have to go for repetitive process from number 1 to entered number 'n'.

->we get square root of number and then its integer value . This we can apply using loop as shown above.

->If we get same value then then we display that.

     for this, we have used 

                if(sqrt(i)==int(sqrt(i))

              it checks square root and its integer value