//program
to reverse a number.
#include<stdio.h>
#include<conio.h>
#include<conio.h>
void main()
{
int n,rem;
printf("enter a number for 'n'\n");
scanf("%d",&n);
{
int n,rem;
printf("enter a number for 'n'\n");
scanf("%d",&n);
while(n!=0)
{
{
rem=n%10;
printf("%d",rem);
n=n/10;
}
getch();
}
--------------------------------------------------------------------------------------------------------
logics in mind:-
>first we enter a number(for 'n').
->If we have number 123 then its reverse is 321. It means, first we have to get 3 then 2 and then 1. ->For this,
->we have to divide by 10 to get last digit.
->Then we display that.
-> to get second digit, we get first 12 and for this , we use 123/10.It is done to get integer part only.
->We repeat this until the value reaches 0. We use loop for this as shown above in the code.
No comments:
Post a Comment