program to display following numeric pattern.

//program to display following numeric pattern.
//               1 2 3 4 5
//               2 4 6 8 10
//               3 6 9 12 15
#include<stdio.h>
#include<conio.h>
void main(void)
{
clrscr();
int i,j;
 for(i=1;i<=3;i++)
   {

  for(j=1;j<=5;j++)

      {
      printf(" %d",i*j);

     }

    printf("\n");

}

getch();

}
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logic in mind:-
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1)we have to display 1 2 3 4 5 then different numbers in second row..
2)we can see there are three rows so we use first loop(outer) with three execution times. And there are    5 columns so we use one another loop for columns(inner).
3) since the pattern is like
        1*1  1*2 1*3 1*4 1*5
       2*1   2*2 2*3 2*4 2*5
and so on.
4) For this, We have used nested loop as shown above.
5)For each value of outer loop(value of 'i'), the inner loop executes 5 times. And it goes to display numbers.
 while displaying, it multiplies both numbers and displays on screen.

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program's screenshot with output:-
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program's screen

output's screen