Lab Work- 4 : Array
Write a C program to input marks of five subjects and display the total marks and average marks.
Write a C program to read the age of 100 persons and count the number of persons in the age group between 50 to 60 years.
Write a C program to input 'n' numbers and display the sum of even and odd numbers respectively.
Write a C program to input 'n' numbers and find out the greatest, smallest and average number.
Write a C program that takes salary of 100 employees and print the salary of the employees in ascending order.
Write a C program to transpose the mxn matrix.
Write a C program to calculate the sum of diagonal matrix.
Write a C program to add two matrices supplying by elements by the user.
solutions:-
q1)Write a C program to input marks of five subjects and display the total marks and average marks.
Ans:-
Algorithm:
step 1: start
step 2:Declare an array marks[5] of integer type
step 3:declare a variable i of integer type
step 4:set total=0
step 4:
execute the loop from i=0 to 4
input marks[i]
total=total+marks[i]
end of loop
step 5:
let average=total/5
step 6: print total,average
step 7:stop
/*program to input marks
of five subjects and display the total marks and average marks.
*/
#include<stdio.h>
int main()
{
int marks[5],total=0;
#include<stdio.h>
int main()
{
int marks[5],total=0;
float average;
for(i=0;i<5;i++)
{
printf("enter marks for %d subject\n",i);
scanf("%d",&marks[i]);
for(i=0;i<5;i++)
{
printf("enter marks for %d subject\n",i);
scanf("%d",&marks[i]);
total=total+marks[i];
}
average=(float)total/5;
printf("total marks=%d,average marks=%f\n",total,average);
return 0;
return 0;
}
Q2)Write a C program to read the age of 100 persons and count the number of persons in the age group between 50 to 60 years.
Ans:-
Algorithm:
step 1: start
step 2:Declare an array age[100]
step 3:declare a variable i of integer type
step 4:set total_age=0
step 5:
execute the loop from i=0 to 100
input age[i]
if age[i]>=50 and age[i]<=60
total_age=total_age+1
end of if
end of loop
step 6: print total_age
step 7:stop
"C" code:
/* program to store age of 'n' persons and count
the number of persons in the age group between 50 to 60 years.
*/
#include <stdio.h>
int main()
{
int age[100],count=0,i;
printf("enter persons age\n");
for(i=0;i<100;i++)
{
printf("enter age for %d person\n",i+1);
scanf("%d",&age[i]);
}
for(i=0;i<100;i++)
{
if(age[i]>50 && age[i]<60 )
#include <stdio.h>
int main()
{
int age[100],count=0,i;
printf("enter persons age\n");
for(i=0;i<100;i++)
{
printf("enter age for %d person\n",i+1);
scanf("%d",&age[i]);
}
for(i=0;i<100;i++)
{
if(age[i]>50 && age[i]<60 )
{
count++;
}
}
count++;
}
}
printf("total persons in range 50 and 60=%d\n",count);
return 0;
}
return 0;
}
q3)Write a C program to input 'n' numbers and display the sum of even and odd numbers respectively.
Ans:-
Algorithm:
step 1: start
step 2:Declare an array numbers[100]
step 3:declare a variable i,size_array of integer type
step 4:set sum_even=0,sum_odd=0
step 5:input size_array
step 6:
execute the loop from i=0 to size_array-1
input numbers[i]
let remainder=numbers[i]/2
if remainder=0
sum_even=sum_even+numbers[i]
else
sum_odd=sum_odd+numbers[i]
end of if
end of loop
step 7: print sum_even,sum_odd
step 8:stop
// program to get sum of even and odd numbers among 'n' numbers
#include <stdio.h>
int main()
{
int a[100],n,i,sum_even=0,sum_odd=0;
printf("enter total number\n");
scanf("%d",&n);
for(i=0;i<n;i++)
{
printf("enter number for location=%d",i);
scanf("%d",&a[i]);
if(a[i]%2==0)
{
#include <stdio.h>
int main()
{
int a[100],n,i,sum_even=0,sum_odd=0;
printf("enter total number\n");
scanf("%d",&n);
for(i=0;i<n;i++)
{
printf("enter number for location=%d",i);
scanf("%d",&a[i]);
if(a[i]%2==0)
{
sum_even=sum_even+a[i];
}
else
{
sum_odd=sum_odd+a[i];
}
}
printf("sum of even =%d,sum of odd numbers=%d\n",sum_even,sum_odd);
printf("sum of even =%d,sum of odd numbers=%d\n",sum_even,sum_odd);
return 0;
}
}
q4)Write a C program to input 'n' numbers and find out the greatest, smallest and average number.
Ans:-
Algorithm:
step 1: start
step 2:Declare an array numbers[100]
step 3:declare a variable i,size_array,average
step 4:set greatest=0,smallest=0,sum=0
step 5:input size_array
step 6:
execute the loop from i=0 to size_array-1
input numbers[i]
sum=sum+numbers[i]
end of loop
step 7: let greatest=numbers[0],smallest=numbers[0]
step 8:
execute the loop from i=0 to size_array-1
if greatest< numbers[i]
greatest=numbers[i]
else if smallest> numbers[i]
smallest=numbers[i]
end of if
end of loop
step 9: average=sum/size_array
step 10:print greatest,smallest,average
step 11:stop
//program to get maximum and minimum value
#include<stdio.h>
int main()
{
int a[200],size,i,max,min,sum=0;
#include<stdio.h>
int main()
{
int a[200],size,i,max,min,sum=0;
float average;
printf("enter value of size to be stored in array\n");
scanf("%d",&size);
for(i=0;i<size;i++)
{
printf("enter value for location=%d",i);
scanf("%d",&a[i]);
printf("enter value of size to be stored in array\n");
scanf("%d",&size);
for(i=0;i<size;i++)
{
printf("enter value for location=%d",i);
scanf("%d",&a[i]);
sum=sum+a[i];
}
max=a[2];
min=a[1];
for(i=0;i<size;i++)
{
if(max<a[i])
{
max=a[i];
}
else if (min>a[i])
{
min=a[i];
}
}
}
max=a[2];
min=a[1];
for(i=0;i<size;i++)
{
if(max<a[i])
{
max=a[i];
}
else if (min>a[i])
{
min=a[i];
}
}
average=(float)sum/size;
printf("the maximum value=%d\n",max);
printf("the minimum value=%d\n",min);
printf("the maximum value=%d\n",max);
printf("the minimum value=%d\n",min);
printf("aveage value=%f\n",average);
return 0;
return 0;
}
q5)Write a C program that takes salary of 100 employees and print the salary of the employees in ascending order.
Ans:-
Algorithm:
step 1: start
step 2:Declare an array salary[100]
step 3:declare a variable i,j,k of integer type
step 4:
execute the loop from i=0 to 99
input salary[i]
end of loop
step 5:
execute the loop from i=0 to 99
execute the loop from j=i+1 to 99
if salary[i]>salary[j]
k=salary[i]
salary[i]=salary[j]
salary[j]=k
end of if
end of loop
end of loop
step 6:
execute the loop from i=0 to 99
print salary[i]
end of loop
step 7:stop
//program to sort 'n' employees salary in ascending order
#include<stdio.h>
int main()
{
int salary[100];
int i,j,k;
printf("enter employees salary\n");
for(i=0;i<100;i++)
{
printf("enter salary for %d person\n",i+1);
scanf("%d",&salary[i]);
#include<stdio.h>
int main()
{
int salary[100];
int i,j,k;
printf("enter employees salary\n");
for(i=0;i<100;i++)
{
printf("enter salary for %d person\n",i+1);
scanf("%d",&salary[i]);
}
for(i=0;i<100;i++)
{
for(j=i+1;j<100;j++)
{
if(salary[i]>salary[j])
{
k=salary[i];
salary[i]=salary[j];
salary[j]=k;
}
}
}
printf("in ascending order,salary are\n");
for(i=0;i<100;i++)
{
printf("%d\n",salary[i]);
for(i=0;i<100;i++)
{
for(j=i+1;j<100;j++)
{
if(salary[i]>salary[j])
{
k=salary[i];
salary[i]=salary[j];
salary[j]=k;
}
}
}
printf("in ascending order,salary are\n");
for(i=0;i<100;i++)
{
printf("%d\n",salary[i]);
}
return 0;
}
return 0;
}
q6)Write a C program to transpose the mxn matrix.
Ans:-
Algorithm:
step 1: start
step 2:Declare an array matrix[100][100]
step 3:declare variables row,col
step 4:declare variables i,j of integer type
step 5:input row,col
step 6:
execute the loop from i=0 to row-1
execute the loop from j=0 to col-1
input matrix[i][j]
end of loop
end of loop
step 7:
execute the loop from i=0 to col-1
execute the loop from j=0 to row-1
print matrix[j][i]
end of loop
end of loop
step 8:stop
code:-
//WAP to transpose a matrix/array of order mxn.
#include<stdio.h>
int main()
{
int matrics_1[100][100];
int i,j;
int total_row,total_col;
printf("enter total number of rows(m)\n");
scanf("%d",&total_row); // for total number of rows of matrix
printf("enter total columns(n)\n");;
scanf("%d",&total_col); // for total number of columns of matrix
printf("enter elements of matrix\n");
for(i=0;i<total_row;i++)
{
for(j=0;j<total_col;j++) // nested loop for input of elements
{
scanf("%d",&matrics_1[i][j]); // getting inputs from user
}
}
printf("before transpose\n"); // message display
for(i=0;i<total_row;i++)
{
for(j=0;j<total_col;j++)
{
printf("%d",matrics_1[i][j]); // display of matrix
}
printf("\n"); // display in next row
}
printf("after transpose\n"); // for transposed matrix
for(i=0;i<total_col;i++)
{
for(j=0;j<total_row;j++)
{
printf("%d",matrics_1[j][i]); // display of matrix with trasnposed elemnts
}
printf("\n");
}
return 0;
}
#include<stdio.h>
int main()
{
int matrics_1[100][100];
int i,j;
int total_row,total_col;
printf("enter total number of rows(m)\n");
scanf("%d",&total_row); // for total number of rows of matrix
printf("enter total columns(n)\n");;
scanf("%d",&total_col); // for total number of columns of matrix
printf("enter elements of matrix\n");
for(i=0;i<total_row;i++)
{
for(j=0;j<total_col;j++) // nested loop for input of elements
{
scanf("%d",&matrics_1[i][j]); // getting inputs from user
}
}
printf("before transpose\n"); // message display
for(i=0;i<total_row;i++)
{
for(j=0;j<total_col;j++)
{
printf("%d",matrics_1[i][j]); // display of matrix
}
printf("\n"); // display in next row
}
printf("after transpose\n"); // for transposed matrix
for(i=0;i<total_col;i++)
{
for(j=0;j<total_row;j++)
{
printf("%d",matrics_1[j][i]); // display of matrix with trasnposed elemnts
}
printf("\n");
}
return 0;
}
q7)Write a C program to calculate the sum of diagonal matrix.
Ans:-
Algorithm
step 1: start
step 2:Declare an array matrix[100][100]
step 3:declare variables row,col
step 4:declare variables i,j of integer type
step 5:set sum=0
step 6:input row,col
step 7:
if row=col
print the addition of diagonal elements is possible
print enter the elements
execute the loop from i=0 to row-1
execute the loop from j=0 to col-1
input matrix[i][j]
if i=j
sum=sum+matrix[i][j]
endif
end of loop
end of loop
else
print addition of diagonal elements for given matrix can not be done
endif
step 8:
print sum
step 9:stop
code:
//WAP to get sum of diagonal elements of an array of order 'mxn'.
#include<stdio.h>
int main()
{
int matrics_1[100][100];
int i,j,sum=0;
int total_row,total_col;
printf("for sum, the matrix must be square\n");
printf("enter total number of rows(m)\n");
scanf("%d",&total_row); // for total number of rows of matrix
printf("enter total columns(n)\n");;
scanf("%d",&total_col); // for total number of columns of matrix
printf("enter elements of matrix\n");
for(i=0;i<total_row;i++)
{
for(j=0;j<total_col;j++) // nested loop for input of elements
{
scanf("%d",&matrics_1[i][j]); // getting inputs from user
}
}
printf("the matrix is\n"); // message display
for(i=0;i<total_row;i++)
{
for(j=0;j<total_col;j++)
{
printf("%d",matrics_1[i][j]); // display of matrix
}
printf("\n"); // display in next row
}
printf("------------------\n"); // for transposed matrix
for(i=0;i<total_row;i++)
{
for(j=0;j<total_col;j++)
{
if(i==j) // testing whether the locations are same or not
{
sum=sum+matrics_1[i][j];
} // display of matrix with trasnposed elemnts
}
printf("\n");
}
printf("sum=%d",sum);
return 0;
}
#include<stdio.h>
int main()
{
int matrics_1[100][100];
int i,j,sum=0;
int total_row,total_col;
printf("for sum, the matrix must be square\n");
printf("enter total number of rows(m)\n");
scanf("%d",&total_row); // for total number of rows of matrix
printf("enter total columns(n)\n");;
scanf("%d",&total_col); // for total number of columns of matrix
printf("enter elements of matrix\n");
for(i=0;i<total_row;i++)
{
for(j=0;j<total_col;j++) // nested loop for input of elements
{
scanf("%d",&matrics_1[i][j]); // getting inputs from user
}
}
printf("the matrix is\n"); // message display
for(i=0;i<total_row;i++)
{
for(j=0;j<total_col;j++)
{
printf("%d",matrics_1[i][j]); // display of matrix
}
printf("\n"); // display in next row
}
printf("------------------\n"); // for transposed matrix
for(i=0;i<total_row;i++)
{
for(j=0;j<total_col;j++)
{
if(i==j) // testing whether the locations are same or not
{
sum=sum+matrics_1[i][j];
} // display of matrix with trasnposed elemnts
}
printf("\n");
}
printf("sum=%d",sum);
return 0;
}
q8)Write a C program to add two matrices supplying by elements by the user.
Ans:-
Algorithm:
step 1: start
step 2:Declare an array matrix1[100][100],matrix2[100][100]
step 3:declare variables row,col
step 4:declare variables i,j of integer type
step 5:input row,col
step 6:
print enter elements of first matrix
execute the loop from i=0 to row-1
execute the loop from j=0 to col-1
input matrix1[i][j]
end of loop
end of loop
step:7
print enter elements of second matrix
execute the loop from i=0 to row-1
execute the loop from j=0 to col-1
input matrix2[i][j]
end of loop
end of loop
step 8:
execute the loop from i=0 to col-1
execute the loop from j=0 to row-1
print matrix1[j][i]+matrix2[j][i]
end of loop
print goto next line
end of loop
step 9:stop
code:
///program to get sum of two matrices of order mxn
#include<stdio.h>
#include<conio.h>
void main()
{
int matrics_1[100][100],matrics_2[100][100];
int i,j;
int total_row,total_col;
printf("enter total number of rows(m)\n");
scanf("'%d",&total_row);
printf("'enter total columns(n)\n");;
scanf("%d",&total__col);
printf("enter elements of first matrix\n");
for(i=0;i<total_row;i++)
{
for(j=0;j<total_col;j++)
{
scanf("%d",&matrics_1[i][j]);
}
}
printf("now enter for second matrix\n");
for(i=0;i<total_row;i++)
{
for(j=0;j<total_col;j++)
{
scanf("%d",&matrics_2[i][j]);
}
}
printf("the summed matrix is\n");
for(i=0;i<total_row;i++)
{
for(j=0;j<total_col;j++)
{
printf("%d",matrics_1[i][j]+matrics_2[i][j]);
}
printf(\n");
}
getch();
}
#include<stdio.h>
#include<conio.h>
void main()
{
int matrics_1[100][100],matrics_2[100][100];
int i,j;
int total_row,total_col;
printf("enter total number of rows(m)\n");
scanf("'%d",&total_row);
printf("'enter total columns(n)\n");;
scanf("%d",&total__col);
printf("enter elements of first matrix\n");
for(i=0;i<total_row;i++)
{
for(j=0;j<total_col;j++)
{
scanf("%d",&matrics_1[i][j]);
}
}
printf("now enter for second matrix\n");
for(i=0;i<total_row;i++)
{
for(j=0;j<total_col;j++)
{
scanf("%d",&matrics_2[i][j]);
}
}
printf("the summed matrix is\n");
for(i=0;i<total_row;i++)
{
for(j=0;j<total_col;j++)
{
printf("%d",matrics_1[i][j]+matrics_2[i][j]);
}
printf(\n");
}
getch();
}
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