using codeblocks
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//division and multiplication of two numbers using pointer //comment of program
#include <stdio.h> //header file
int main()
{
float *p,*p1; //two pointer declaration
float x,y; //variable declaration
printf("enter two values for x and y\n");//prints message
scanf("%f%f",&x,&y); // gets input
p=&x,p1=&y; //assigning address to that pointer
printf("the address of x(%f) is=%f\n",x,p);//display of that address
printf("the address of y(%f) is=%f\n",y,p1);//display of address of second variable
printf("the product=%f\n",(*p)*(*p1));
//display of multiplication stored in that address. we display that using indirection operator
printf("the quotient=%f",(*p)/(*p1));//display of quotient part
return 0;
}
------------------------------------------------------------------------
//division and multiplication of two numbers using pointer //comment of program
#include <stdio.h> //header file
int main()
{
float *p,*p1; //two pointer declaration
float x,y; //variable declaration
printf("enter two values for x and y\n");//prints message
scanf("%f%f",&x,&y); // gets input
p=&x,p1=&y; //assigning address to that pointer
printf("the address of x(%f) is=%f\n",x,p);//display of that address
printf("the address of y(%f) is=%f\n",y,p1);//display of address of second variable
printf("the product=%f\n",(*p)*(*p1));
//display of multiplication stored in that address. we display that using indirection operator
printf("the quotient=%f",(*p)/(*p1));//display of quotient part
return 0;
}
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using turboc++
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//division and multiplication of two numbers using pointer //comment of program
#include <stdio.h> //header file
#include<conio.h>
int main()
{
float *p,*p1; //two pointer declaration
float x,y; //variable declaration
printf("enter two values for x and y\n");//prints message
scanf("%f%f",&x,&y); // gets input
p=&x,p1=&y; //assigning address to that pointer
printf("the address of x(%f) is=%f\n",x,p);//display of that address
printf("the address of y(%f) is=%f\n",y,p1);//display of address of second variable
printf("the product=%f\n",(*p)*(*p1));
//display of multiplication stored in that address. we display that using indirection operator
printf("the quotient=%f",(*p)/(*p1));//display of quotient part
getch();
return 0;
}
