program to get sum of all digits present in a number.

//program to get sum of all digits present in a number.

#include<stdio.h>
#include<conio.h>

void main()
{
   int n,rem,sum=0;
   printf("enter a number for 'n'\n");
  scanf("%d",&n);

  while(n!=0)
    {

      rem=n%10;

       sum=sum+rem;

        n=n/10;    

   }

   printf("the sum=%d",sum);

getch();

}

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logics in mind:-

>first we enter a number(for 'n').

->to get sum of digits,first we have to get all digits one by one.If we have number 123 then its sum is 3+2+1=6. It means, first we have to get 3 then 2 and then 1.        

     ->For this, 

                 ->we have to divide by 10 to get last digit. 

                ->Then we go for sum using sum=sum+digit.

                -> to get second digit, we get first 12 and for this , we use 123/10.It is done to get integer                           part  only.

->We repeat this until the value reaches 0 and last sum is received. We use loop for this as shown above in the code.             

->then final sum is displayed.