program to display following numeric/star pattern.

//program to display following numeric pattern.
//      5
//      44
//      333
//      2222
//      11111        
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j;
for(i=5;>=1;i--)
  {
     for(j=5;j>=i;j--)
          {
                printf("%d",i);
          }
       printf("\n");
 }
getch();
}
--------------------------------------------------------
logics in mind:
----------------------
1)we have to display 5,then 44, then 333,so on.  we use loop for this.
 2)since the displays are in repetitive form ,,we set up the loop in nested form such that
        internal loop executes first  time with display of numbers(above) which it takes from outer loop,then 
two times  and it goes on decreasing.
3)First loop(outer) takes value 5 and assigns to inner.The inner executes one time with display taken from outer loop.
4)next time, the outer loop takes the value 4 and transfers to inner loop, it displays number taken from outer loop again and again.and it goes on.
............................................................................................
if you want to display "*" then use "*" in printf function.                                                            

program to display following numeric/star pattern.

//program to display following numeric/star pattern.
//     11111
//     2222
//     333
//     44
//     5            
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j;
for(i=1;<=5;i++)
  {
     for(j=5;j>=i;j--)
          {
                printf("%d",i);
          }
       printf("\n");
 }
getch();
}
--------------------------------------------------------
logics in mind:
----------------------
1)we have to display 1,then 2222, then 333,so on.  we use loop for this.
 2)since the displays are in repetitive form ,,we set up the loop in nested form such that
        internal loop executes first  time with display of numbers(above) which it takes from outer loop,then 
four times  and it goes on decreasing.
3)First loop(outer) takes value 1 and assigns to inner.The inner executes five times with display taken from outer loop.
4)next time, the outer loop takes the value 2 and transfers to inner loop, it displays number taken from outer loop again and again.and it goes on.
............................................................................................
if you want to display "*" then use "*" in printf function.

program to display following numeric/star pattern.

//program to display following numeric pattern.
//      1
//      12
//      123
//      1234
//      12345 
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j;
for(i=1;i<=5;i++)
  {
     for(j=1;j<=i;j++)
          {
                printf("%d",j);
          }
       printf("\n");
 }
getch();
}
--------------------------------------------------------
logics in mind:
----------------------
1)we have to display 1,then 12, then 1233,so on.  we use loop fo this.
 2)since the displays are in repetitive form ,,we set up the loop in nested form such that
        internal loop executes first one  time with display of numbers(above),then two times  and it goes on increasing.
3)First loop(outer) takes value 1 and assigns to inner.The inner executes one times with display.
4)next time, the outer loop takes the value 2 and transfers to inner loop, it displays again and again.
and it goes on
............................................................................................
if you want to display "*" then use "*" in printf function.

program to display star/number pattern

//program to display given star/number pattern
//      12345
//        1234
//          123
//            12
//              1
#include<stdio.h>
#include<stdio.h>
void main()
{
clrscr();
int i,j,k,sp=5;
 for(i=5;i>=1;i--)
   {
               for(k=sp;k>=i;k--)
                 {
                  printf(" ");
                  }
                        for(j=1;j<=i;j++)
                           {
                            printf("%d",j);
                          }
           printf("\n");
  }
getch();
}
---------------------------------
logics in mind
-------------------------------
1)we have to display 1,2,3,4,5 so we use loop.
 2)since the displays are in repetitive form ,,we set up the loop in nested form such that
        internal loop executes 5 times with display of numbers(above).
3)if we look carefully to given pattern we can see there space increased after each display. for this, we have used loop. in each display, it increases space and then it goes for next display.
3)First loop(outer) takes value 5 and assigns to inner.The inner executes 5 times with display.
4)next time, the outer loop takes the value 4 and transfers to inner loop, it displays again and again.
and it goes on

...................................................
if you wan to display star then put "*" in printf

program to display following numeric pattern.

//program to display following numeric pattern.
//      12345
//      1234
//      123
//      12
//      1
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j;
for(i=5;i>=1;i--)
  {
     for(j=1;j<=i;j++)
          {
                printf("%d",j);
          }
       printf("\n");
 }
getch();
}
--------------------------------------------------------
logics in mind:
----------------------
1)we have to display 1,2,3,4,5 so we use loop.
 2)since the displays are in repetitive form ,,we set up the loop in nested form such that
        internal loop executes 5 times with display of numbers(above).
3)First loop(outer) takes value 5 and assigns to inner.The inner executes 5 times with display.
4)next time, the outer loop takes the value 4 and transfers to inner loop, it displays again and again.
and it goes on



        

program to display first 5 Armstrong numbers between 0 and 1000.

//program to display first 5 Armstrong numbers between 0 and 1000

//we are taking numbers with three digits
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
clrscr();
int i=1,rem,k,sum=0,count=0;
while(i<=1000)
{
     k=i;
     sum=0;
while(k!=0)
  {
    rem=k%10;
    sum=sum+pow(rem,3);
    k=k/10;
  }

 if(sum==i)
 {

          count++;

           if(count<=5)

               {   printf("%d\n",i);

                }  }
 sum=0;
 i++;

}
getch();
}
-----------------------------------------------------------------------------------------------------------------------------------------------------------
logics in mind:-
-------------------
->we have to display Armstrong numbers in given range 0 and 1000.Armstrong can be for 3/4 digits numbers.
   Here we taking 3 digits only.

->First  we take first number (k) then we apply following method        

                  ->For this, 

                 ->we have to divide by 10 to get last digit as remainder 

                 ->we find its cube and then go for sum

                -> to get second digit, we get first 12 and for this , we use 123/10.It is done to get integer                           part  only.

                  ->then we compare the number 'i' with that sum. If they are same then we display that.

->We repeat this until the value reaches 0 and for all numbers and individually. We use loop for this as shown above in the code.     

->as the first number is checked, we , once again, assign value '0' to sum to check next value.And this goes on. 

->while displaying Armstrong number, we also count it.If it is less than/equal to 5 then we display that.

program to display all Armstrong numbers between 0 and 100 solution here we are taking Armstrong number with 3 digit. but more digit also can be taken

//armstrong numbers lying in given range 0 and 1000
//we are taking numbers with three digits
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
clrscr();
int i=1,rem,k,sum=0;
while(i<=1000)
{
     k=i;
     sum=0;
while(k!=0)
 {
   rem=k%10;
   sum=sum+pow(rem,3);
   k=k/10;
 }

if(sum==i)
{
      printf("%d\n",i);

}
sum=0;
 i++;

}
getch();
}
-----------------------------------------------------------------------------------------------------------------------------------------------------------
logics in mind:-
-------------------
->we have to display Armstrong numbers in given range 0 and 1000.Armstrong can be for 3/4 digits numbers.
   Here we taking 3 digits only.

->First  we take first number (k) then we apply following method        

                  ->For this, 

                 ->we have to divide by 10 to get last digit as remainder 

                 ->we find its cube and then go for sum

                -> to get second digit, we get first 12 and for this , we use 123/10.It is done to get integer                           part  only.

                  ->then we compare the number 'i' with that sum. If they are same then we display that.

->We repeat this until the value reaches 0 and for all numbers and individually. We use loop for this as shown above in the code.     

->as the first number is checked, we , once again, assign value '0' to sum to check next value.And this goes on.