WEAP to display following star pattern

/*program to display following

* * * * *
* * * * *
* * * * *
* * * * *
* * * * *

*/
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,j;
for(i=1;i<=5;i++)      //for number of rows. there are five rows so loop moves fives times
  {
    for(j=1;j<=5;j++) //it displays star five times.It displays in columns
      {
printf("* ");
      }
    printf("\n");
}
getch();
}

------------------------------------
logic in mind:-
1)we have to display five rows and five columns.
2) we have used outer loop five times.
3)and inner loop five times.
-------------------------------
 program 's screenshot

output

write a program to display plus pattern

/*to display following
  +
               +
               +
               +
   + + + + + + + + +
              +
              +
              +
              +
              +
*/
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
char a='+';
int i,j,k=0,k1;
for(i=4;i>=0;i--)
{
  for(k1=-3;k1<=5;k1++)
     {
       printf(" ");
     }
  for(j=1;j<=1;j++)
    {
      printf("%c",a);
    }
  printf("\n");
}
for(i=1;i<=9;i++)
{
for(k1=5;k1<=5;k1++)
     {
       printf(" ");
     }
printf("+");
}
for(i=4;i>=0;i--)
{
  for(k1=-3;k1<=5;k1++)
     {
       printf(" ");
     }
  for(j=1;j<=1;j++)
    {
      printf("%c",a);
    }
  printf("\n");
}
getch();

}

-------------------

logic in mind:-
1)for this display, we have three parts.
      first part is upper 
      second part is horizontal
      third part is vertical form(look circled part)
2) First we display upper part using three loops.
          outer loop is for number of rows
           inner is for space(constant)
          inner most is for display
3) similarly, for second part we have done. ----------------------
program's screenshot:-

----------------------------
program's output:-

WAP to get following alphabetical pattern

/*WAP to get following

ABCDE
ABCD
ABC
AB
A
*/
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
char a='A';
int i,j,k=0;
for(i=4;i>=0;i--)
{
  for(j=0;j<=i;j++)
    {
      printf("%c",a+j);
    }
  printf("\n");

}
getch();
}
-----------------
logic in mind
1) we have to display different characters in different rows and columns.
2)there are five rows and columns. The column is decreased in each display.
3)for this, we have used first loop for different rows.
4)second loop is for display. It fetches value from first loop and displays different character.
5)second loop is taken from value 0.because,  in each display, the character changes so. 
for more: look down.
--------------
program screenshot:-

program output:-

to display letters' pattern

/*to display following
A
AB
ABC
ABCD
ABCDE
*/
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
char a='A';
int i,j,k=0;
for(i=1;i<=5;i++)
{
  for(j=0;j<i;j++)
    {
      printf("%c",a+j);
    }
  printf("\n");

}
getch();
}
-------------------
logic in mind:-
-------------
1) we have to display different characters in different rows and columns.
2)there are five rows and columns. The column is decreased in each display.
3)for this, we have used first loop for different rows.
4)second loop is for display. It fetches value from first loop and displays different character.
5)second loop is taken from value 0.because,  in each display, the character changes so.
for more: look down.
program screenshot:-

program output:-

to display letters' pattern

/*to display following
A
AB
ABC
ABCD
ABCDE
*/
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
char a='A';
int i,j,k=0;
for(i=1;i<=5;i++)
{
  for(j=0;j<i;j++)
    {
      printf("%c",a+j);
    }
  printf("\n");
  //a++;
}
getch();
}
-------------------
logic in mind:-
-------------
1) we have to display different characters in different rows and columns.
2)there are five rows and columns. The column is decreased in each display.
3)for this, we have used first loop for different rows.
4)second loop is for display. It fetches value from first loop and displays different character.
5)second loop is taken from value 0.because,  in each display, the character changes so.
for more: look down.
program screenshot:-

program output:-

to display letters' pattern

/*to display following
A
AB
ABC
ABCD
ABCDE
*/
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
char a='A';
int i,j,k=0;
for(i=1;i<=5;i++)
{
  for(j=0;j<i;j++)
    {
      printf("%c",a+j);
    }
  printf("\n");

}
getch();
}
-------------------
logic in mind:-
-------------
1) we have to display different characters in different rows and columns.
2)there are five rows and columns. The column is decreased in each display.
3)for this, we have used first loop for different rows.
4)second loop is for display. It fetches value from first loop and displays different character.
5)second loop is taken from value 0.because,  in each display, the character changes so.
for more: look down.
program screenshot:-

program output:-

Write a program to get following numeric pattern.

/*Write a program to get following numeric pattern.
0
01
012
0123                                                                                                                    
012
01
0
*/
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,j;
for(i=0;i<=3;i++)
{
 for(j=0;j<=i;j++)
   {
      printf("%d",j);

   }
      printf("\n");
}
for(i=2;i>=0;i--)
{
 for(j=0;j<=i;j++)
   {
      printf("%d",j);

   }
      printf("\n");
}
getch();
}

-------------------------------------------------

logic in mind:-

1) we have to display given pattern.It has two parts

      first part is:upper part .i..e

        0

       01
       012
        0123   

  and second part is

     012
     01
     0
2)for first part, like shown below, we use loop to fetch value from outer loop and displaying from inner loop
3)for second part, we use once again loop with one less value. We fetch that and display from inner loop
just look down.

program's screenshot:

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output screen: