Tutorial section of "C' language

click the unit given here to read that section thoroughly.

program to know ascii value

// program to know ascii value
#include<stdio.h>
#include<conio.h>
void main()
{
char a;
a=getchar();
printf("its ascii value=%d",a);
getch();
}

program to convert total seconds into hour,minutes and seconds

// program to convert total seconds into hour,minutes and seconds
#include<stdio.h> #include<conio.h> void main() { clrscr(); int total_seconds,hr,minutes,seconds; printf("enter total seconds \n"); scanf("%d",&total_seconds); hr=total_seconds/3600; // to get hour after dividing total seconds by 3600 printf("hours =%d\n",hr); hr=total_seconds%3600; // after getting hours, we have to get total left second minutes=hr/60; // to get total minutes printf("total minutes=%d\n",minutes); seconds=hr%60; // it gives total left seconds as seconds after getting months printf("the seconds=%d\n",seconds); getch(); }

note:

Here I have used same variable again and again. But I you want then you can use different variable

program to convert days into year ,month and days

// program to convert total days into year,month and days #include<stdio.h> #include<conio.h> void main() { clrscr(); int total_days,year,month,days; printf("enter total days \n"); scanf("%d",&total_days); year=total_days/365; // to get year after dividing total days by 365 printf("year =%d\n",year); year=total_days%365; // after getting years, we have to get total left days month=year/30; // to get total months printf("total months=%d\n",month); days=year%30; // it gives total left days as days after getting months printf("the days=%d\n",days); getch(); }

note:

Here I have used same variable again and again. But I you want then you can use different variable.

program to get values in of x in quadratic equation

//program to get values of x in quadratic equation
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
float a,b,c,x1,x2;
printf("enter values of a,b and c\n");
scanf("%f%f%f",&a,&b,&c);
x1=(-b+sqrt(b*b-4*a*c))/2*a;
x2=(-b-sqrt(b*b-4*a*c))/2*a;
printf("the first value=%f\n",x1);
printf("second value is=%f",x2);
getch();
}

note:

according to formula the condition should be satisfied.like
1) (b²-4ac)>0 i.e. b²>4ac
2)a>0 for 2a
otherwise the program terminates abnormally without any result.
later we will see this program with 'if' structure'.

Logically that is said to be right.

program to get total and percentage of a student

// program to get total and percentage of a student

#include<stdio.h>

#include<conio.h>
#include<math.h>

void main()

{

int english,maths,physics,chemistry;
float total,percentage;

printf(“enter marks of different subjects \n”);

scanf(“%d%d%d%d”,&english,&maths,&physics,&chemistry);

total=english+maths+physics+chemistry;
percentage=(float)total/4; //called type casting to convert total/4 into floating value

printf(“the total marks is=%f\ and percentage=%f\n”,total,percentage);

getch();
}

note:
you can also use like,
percentage=(float)(total/4);
 or
percentage=float(total/4);
you get same output.

program to get value of f(x)

// program to get value of f(x)=x²+2x+3

#include<stdio.h>

#include<conio.h>
#include<math.h>

void main()

{

float x,f_x;

printf(“enter x \n”);

scanf(“%f”,&x);

f_x=(pow(x,2)+2*x+3); //pow() function exists inside math.h

printf(“the result is=%f\n”,f_x);

getch();
}