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program to display given numeric pattern

//program to display following numeric pattern.
//               1 2 3 4 5
//               6 7 8 9 10
//               11 12 13 14 15
#include<stdio.h>
#include<conio.h>
void main(void)
{
clrscr();
int i,j,k=0;
 for(i=1;i<=3;i++)
   {
   for(j=1;j<=5;j++)
       {
       printf(" %d",j+k);
      }
    printf("\n");
k=k+5;}
getch();
}
-----------------------------------
logic in mind:-
------------------------------------
1)we have to display 1 2 3 4 5 then different numbers in second row..
2)we can see there are three rows so we use first loop(outer) with three execution times. And there are         5 columns so we use one another loop(five times execution) for columns(inner).
3) since the pattern is like
        1+0   2+0   3+0  4+0  5+0
       1+5   2+5   3+5   4+5  5+5
and so on.
4) For this, We have used nested loop as shown above and one variable named k with initial value '0'.
5)For each value of outer loop(value of 'i'), the inner loop executes 5 times. And it goes to display numbers.
 while displaying, it adds both numbers (j and k)and displays on screen.
6)In second display the value of k is increased by 5 as shown above.
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program's screenshot
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output is:-
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program to display following numeric pattern.

//program to display following numeric pattern.
//               1 2 3 4 5
//               2 4 6 8 10
//               3 6 9 12 15
#include<stdio.h>
#include<conio.h>
void main(void)
{
clrscr();
int i,j;
 for(i=1;i<=3;i++)
   {

  for(j=1;j<=5;j++)

      {
      printf(" %d",i*j);

     }

    printf("\n");

}

getch();

}
-----------------------------------
logic in mind:-
------------------------------------
1)we have to display 1 2 3 4 5 then different numbers in second row..
2)we can see there are three rows so we use first loop(outer) with three execution times. And there are    5 columns so we use one another loop for columns(inner).
3) since the pattern is like
        1*1  1*2 1*3 1*4 1*5
       2*1   2*2 2*3 2*4 2*5
and so on.
4) For this, We have used nested loop as shown above.
5)For each value of outer loop(value of 'i'), the inner loop executes 5 times. And it goes to display numbers.
 while displaying, it multiplies both numbers and displays on screen.

  ------------------
program's screenshot with output:-
----------------------------------------------------
program's screen
output's screen


program to display following numeric pattern

program to display following numeric pattern.
//                   1 
//                 2 2
//               3 3 3
//              4 4 4 4
//            5 5 5 5  5     
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,j,k,sp=15;
 for(i=1;i<=5;i++)
   {
               for(k=sp;k>=i;k--)
                 {
                  printf(" ");
                  }
                        for(j=1;j<=i;j++)
                           {
                            printf(" %d",i);
                          }
           printf("\n");
  }
getch();
}
-----------------------------
logic in mind:-
------
1)we have to display 1,2 2,3 3 3 and so on. We use loop for this.
 2)since the displays are in repetitive form ,,we set up the loop in nested form such that
        internal loop executes from 1 to 5 times with display of numbers(above).Because numbers are from 1 then        2 then 3....To display number, we take variable 'i' from outer loop.It's repeated by inner loop.
3)if we look carefully to given pattern, we can see there space decreased after each display. for this, we have used loop. in each display, it decreases space and then it goes for next display.
3)First loop(outer) takes value 5 and assigns to inner.The inner executes 5 times with display.
4)next time, the outer loop takes the value 1 and transfers to inner loop, it displays again and again.
and it goes on
-----------
note:
--------------
if you want to display "*" (star) then use "*" in printf function. ------------------------

                                            

program to display star pattern

//program to display following star pattern.
//              *
//           * *                                                                                                          
//        * * *
//     * * * *
//  * * * * *   
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,j,k,sp;
 for(i=1;i<=5;i++)
   { sp=i;
         for(k=sp;k<=10;k++)
           {
               
                     printf(" ");

              }
                     
    for(j=1;j<=i;j++)
                       {
                       printf("*");
                     }      
    printf("\n"); 
}
getch();
}
---------------------------------
logics in mind
-------------------------------
1)we have to display *,**,***, and so  on .we use loop.
 2)since the displays are in repetitive form ,,we set up the loop in nested form such that
        internal loop executes 5 times(maximum) with display of stars(above).
3)if we look carefully to given pattern we can see there space decreased after each display. for this, we have used loop. in each display, it decreases space and then it goes for next display. To decrease space, it taks value from outer loop i.e. value from variable 'i'.
3)First loop(outer) takes value 1 and assigns to inner.The inner executes 1 time/s with display.
4)next time, the outer loop takes the value 2 and transfers to inner loop, it displays again and again.
and it goes on

.

program to display given star/number pattern

//program to display given star/number pattern
//      1 1 1 1 1
//         2 2 2
//            3
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,j,k,sp=5,m=1;
 for(i=5;i>=1;i=i-2)
   {
               for(k=sp;k>=i;k--)
                 {
                  printf(" ");
                  }
                        for(j=1;j<=i;j++)
                           {
                            printf(" %d ",m);
                          }
           printf("\n");
     m++;
  }
getch();
}
---------------------------------
logics in mind
-------------------------------
1)we have to display 1 1 1 1 1 so we use loop.
 2)since the displays are in repetitive form ,,we set up the loop in nested form such that
        internal loop executes 5 times with display of numbers(above),then 3 times and then 1 time.
3)if we look carefully to given pattern, we can see there space increased after each display. for this, we have used loop. in each display, it increases space and then it goes for next display.
3)First loop(outer) takes value 5 and assigns to inner.The inner executes 5 times with display.
4)next time, the outer loop takes the value 3 and transfers to inner loop, it displays again and again.
and it goes on
-----------
note:
--------------
if you want to display "*" (star) then use "*" in printf function.   

program to display following numeric/star pattern.

//program to display following numeric/star pattern.          
 // 1 1 1 1 1
 // 2 2 2 2 2
//  3 3 3 3 3
//  4 4 4 4 4
#include <stdio.h>
#include<conio.h>
void main() { int i,j; for(i=1;i<=4;i++) { for(j=1;j<=5;j++) { printf(" %d ",i); } printf("\n"); } getch(); }
-----------------------------


Logic in mind:
----------------------

1)we have to display 1 1 1 1 1,then 2 2 2 2 2 2 ,and so on.  we use loop for this.
      We have to know one thing here that, there are four rows and five columns. so for this, we use nested loop. The outer loop is for rows and inner loop is for columns.
 2)accordingly we set up the loops.since the displays are in repetitive form ,,we set up the loop in nested form such that
        internal loop executes first  time with display of numbers(above) taken from outer loop and that is '1' first and '2' ..., 
five  times
.3)First loop(outer) takes value 1 and assigns to display unit(printf).The inner executes five times with display taken from outer loop.
4)next time, the outer loop takes the value 2 and transfers to  display unit. the inner loop displays the number again and again(five times)and it goes on.
............................................................................................
if you want to display "*" then use "*" in printf function.                                                            

program to display following numeric/star pattern.

//program to display following numeric pattern.
//      5
//      44
//      333
//      2222
//      11111        
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j;
for(i=5;>=1;i--)
  {
     for(j=5;j>=i;j--)
          {
                printf("%d",i);
          }
       printf("\n");
 }
getch();
}
--------------------------------------------------------
logics in mind:
----------------------
1)we have to display 5,then 44, then 333,so on.  we use loop for this.
 2)since the displays are in repetitive form ,,we set up the loop in nested form such that
        internal loop executes first  time with display of numbers(above) which it takes from outer loop,then 
two times  and it goes on decreasing.
3)First loop(outer) takes value 5 and assigns to inner.The inner executes one time with display taken from outer loop.
4)next time, the outer loop takes the value 4 and transfers to inner loop, it displays number taken from outer loop again and again.and it goes on.
............................................................................................
if you want to display "*" then use "*" in printf function.